您需要添加到year
列JD
轉換to_timedelta
:
df['date'] = pd.to_datetime(df.year, format='%Y') + pd.to_timedelta(df.JD - 1, unit='d')
print (df)
ad_name adl_name year JD date
0 united_states_of_america colorado 2000 1 2000-01-01
1 united_states_of_america colorado 2000 2 2000-01-02
2 united_states_of_america colorado 2000 3 2000-01-03
3 united_states_of_america colorado 2000 4 2000-01-04
4 united_states_of_america colorado 2000 5 2000-01-05
樣品與JD=32
和JD=366
:
print (df)
ad_name adl_name year JD
0 united_states_of_america colorado 2000 32
1 united_states_of_america colorado 2000 366
df['date'] = pd.to_datetime(df.year, format='%Y') + pd.to_timedelta(df.JD - 1, unit='d')
print (df)
ad_name adl_name year JD date
0 united_states_of_america colorado 2000 32 2000-02-01
1 united_states_of_america colorado 2000 366 2000-12-31
我不確定我是否理解'茱莉安日'。它與「天」不同嗎? – jezrael
朱連安日是一年中的一天,從1到365/366 – user308827