C＃託管DirectX - 我如何旋轉網格到任何矢量？

我想寫一個函數，我可以在三維空間中將網格投影到一個點上。C＃託管DirectX - 我如何旋轉網格到任何矢量？

但我無法找到我的解決方案的任何示例。

它應該看起來像下面的代碼：

public void RotateMesh(Vector3 MeshPos, Vector3 TargedPos) 
{ 
    ... Do something 
}

但我不知道我怎麼可以旋轉MeshPos到TargetPos。

如果有人能解釋它會很好。

我想我需要一個Matrix作爲返回值，因爲我需要爲我的SelectedPoint矩陣的繪製函數添加一個Matrix。

繪圖功能：

Matrix SelectedPoint = Matrix.Scaling(0.1f, 0.1f, 0.1f) * Matrix.Translation(IntersectVector) * OldMatrix; 
       gameengine.m_Device.Transform.World = SelectedPoint; 
       for (int i = 0; i < Burg.MeshObject.NumberAttributes; i++) 
       { 
        gameengine.m_Device.Material = Burg.material[i]; 
        gameengine.m_Device.SetTexture(0, Burg.texture[i]); 
        Burg.MeshObject.DrawSubset(0); 
       } 


public Matrix RotateMesh(Vector3 MeshPos, Vector3 TargedPos) 
{ 
    ... Do something 
    return AMatrix; 
}

那麼我tryed以下，但財產以後已經倒..

Vector3 target =new Vector3(0.0001f, 0.0001f, 0.0001f); 
      Vector3 vFront = target - IntersectVector; 
      vFront.Normalize(); 

      Vector3 vLeft = Vector3.Cross(vFront, new Vector3(0, 1, 0)); 
      vLeft.Normalize(); 
      Vector3 vUp = Vector3.Cross(vLeft, vFront); 
      vUp.Normalize(); 

      Matrix mBase = Matrix.Identity; 
      mBase.M11 = vLeft.X; 
      mBase.M21 = vLeft.Y; 
      mBase.M31 = vLeft.Z; 
      mBase.M12 = vUp.X; 
      mBase.M22 = vUp.Y; 
      mBase.M32 = vUp.Z; 
      mBase.M13 = vFront.X; 
      mBase.M23 = vFront.Y; 
      mBase.M33 = vFront.Z; 

      Matrix TestMatrix = gameengine.camera._viewMatrix; 
      TestMatrix.Invert(); 

      gameengine.m_Device.RenderState.DitherEnable = true; 
      gameengine.m_Device.RenderState.ZBufferEnable = true; 
      gameengine.m_Device.VertexFormat = SEarth.MeshObject.VertexFormat; 
      gameengine.m_Device.RenderState.CullMode = Cull.None; 


      if (IntersectVector != Vector3.Empty) 
      { 
       Matrix SelectedPoint = Matrix.Scaling(0.1f, 0.1f, 0.1f) * mBase * Matrix.Translation(IntersectVector) * OldMatrix;

現在好了，我tryed其他的東西..但網不旋轉，變形！怎麼了？

OldMatrix *= Matrix.RotationX(CubeRotX) * Matrix.RotationY(CubeRotY); 


      Vector3 target =new Vector3(0.0001f, 0.0001f, 0.0001f); 
      Vector3 vFront = target - IntersectVector; 
      vFront.Normalize(); 

      Vector3 vLeft = Vector3.Cross(vFront, new Vector3(0, 1, 0)); 
      vLeft.Normalize(); 
      Vector3 vUp = Vector3.Cross(vLeft, vFront); 
      vUp.Normalize(); 

      Matrix mBase = Matrix.Identity; 
      mBase.M11 = vLeft.X; 
      mBase.M12 = vUp.X; 
      mBase.M13 = vFront.X; 
      mBase.M14 = 0.0f; 
      mBase.M21 = vLeft.Y; 
      mBase.M22 = vUp.Y; 
      mBase.M23 = vFront.Z; 
      mBase.M24 = 0.0f; 
      mBase.M31 = vLeft.Z; 
      mBase.M32 = vUp.Z; 
      mBase.M33 = vFront.Z; 
      mBase.M34 = 0.0f; 
      //mBase.M41 = IntersectVector.X; 
      //mBase.M42 = IntersectVector.Y; 
      //mBase.M43 = IntersectVector.Z; 
      mBase.M41 = 0; 
      mBase.M42 = 0; 
      mBase.M43 = 0; 
      mBase.M44 = 1.0f; 

      if (IntersectVector != Vector3.Empty) 
      { 
       Matrix SelectedPoint = Matrix.Scaling(0.1f, 0.1f, 0.1f) * mBase * Matrix.Translation(IntersectVector) * OldMatrix; 
       gameengine.m_Device.Transform.World = SelectedPoint; 
       for (int i = 0; i < Burg.MeshObject.NumberAttributes; i++) 
       { 
        gameengine.m_Device.Material = Burg.material[i]; 
        gameengine.m_Device.SetTexture(0, Burg.texture[i]); 
        Burg.MeshObject.DrawSubset(0); 
       } 
      }

左手和右手矩陣有什麼不同？我想我是非常棒的。

我應該解釋一下我PROGRAMM確定它不會工作.. ..有與位置「的Vector3（0,0,0）」

如果我在球上點擊某處..一城一球將放置在相交座標上。

目前的最佳解決方案是創建LookAtL矩陣，但城堡不會面對相交向量中的向量（0,0,0）。

更新2013年5月1日

Planet with Wire and the Castle on the Click position

Planet with Solid and the Castle on the Click position

這裏是當前功能

gameengine.m_Device.RenderState.FillMode = FillMode.Solid; 
      OldMatrix *= Matrix.RotationX(CubeRotX) * Matrix.RotationY(CubeRotY); 


      Vector3 target =new Vector3(0.0001f, 0.0001f, 0.0001f); 
      Vector3 vFront = target - IntersectVector; 
      vFront.Normalize(); 

      Vector3 vLeft = Vector3.Cross(vFront, new Vector3(0, 1, 0)); 
      vLeft.Normalize(); 
      Vector3 vUp = Vector3.Cross(vLeft, vFront); 
      vUp.Normalize(); 

      Vector3 vRigth = Vector3.Cross(vUp, vFront); 


      Matrix mBase = Matrix.Identity; 
      mBase.M11 = vLeft.X; 
      mBase.M12 = vUp.X; 
      mBase.M13 = vFront.X; 
      mBase.M21 = vLeft.Y; 
      mBase.M22 = vUp.Y; 
      mBase.M23 = vFront.Z; 
      mBase.M31 = vLeft.Z; 
      mBase.M32 = vUp.Z; 
      mBase.M33 = vFront.Z; 

      //Matrix ObjectMatrix = Matrix.LookAtLH(IntersectVector, new Vector3(0, 0, 0), new Vector3(0, 1, 0)); 
      Matrix ObjectMatrix = Matrix.LookAtLH(vFront, vUp, vLeft); 

      if (IntersectVector != Vector3.Empty) 
      { 
       // Translation * Base * Rotation * Scaling 
       Matrix SelectedPoint = Matrix.Identity * ObjectMatrix *Matrix.Scaling(0.3f, 0.3f, 0.3f) * Matrix.Translation(IntersectVector) *OldMatrix; 
       //SelectedPoint.M41 = IntersectVector.X; 
       //SelectedPoint.M42 = IntersectVector.Y; 
       //SelectedPoint.M43 = IntersectVector.Z; 
       //SelectedPoint *= OldMatrix; 

       gameengine.m_Device.Transform.World = SelectedPoint; 
       for (int i = 0; i < Burg.MeshObject.NumberAttributes; i++) 
       { 
        gameengine.m_Device.Material = Burg.material[i]; 
        gameengine.m_Device.SetTexture(0, Burg.texture[i]); 
        Burg.MeshObject.DrawSubset(0); 
       } 
      } 
      Material deviceMat = gameengine.m_Device.Material; 
      //gameengine.m_Device.Material.AmbientColor = ColorValue.FromArgb(161613); 


      //testsphere.DrawSubset(0); 
      gameengine.m_Device.Material = deviceMat; 
//gameengine.m_Device.RenderState.FillMode = FillMode.WireFrame;

來源

2013-04-29 ZeraTFK

你真的是旋轉？或者你想要一個網格來面對目標位置？因此，您可以使用基礎變換，您可以將網格和目標之間的矢量作爲前部，向上矢量和左右兩邊的交叉點構建。 – Gnietschow 2013-04-29 22:10:03

嗨Gnietschow，是的，我的意思是面對目標位置的網格。以及杜ü意味着與「網和taget之間的向量作爲正面且載體」，我需要從MeshVector.left和TargetVector.Left跨MeshVector.Up和TargetVector.Up的dotproduct？ – ZeraTFK 2013-04-29 22:20:39

我的意思是'Front =（目標位置）.Normalize; Left = Cross（Front，Vector3（0,1,0））。 Up = Cross（Left，Front）.Normalize;'在這個基礎上，你可以建立一個基礎變換的矩陣，它將你的網格映射到正確的方向。 – Gnietschow 2013-04-29 22:26:28

爲了使對象面有一定的方向，用一個攝像機視圖矩陣。該矩陣將對象從空間中轉換爲面向查看方向的空間，將其轉換爲面向z軸的空間。

爲了您的目的，您應該反轉此矩陣，它會將Z軸映射到您用來創建視圖矩陣的lookdirection。

僞代碼：

ObjectMatrix = Matrix.Invert(Matrix.CreateLookAtLH(dir,up,right));

這將使-z軸面中的對象的dir方向。

來源

2013-04-30 21:18:04 MHGameWork

那麼網格將會轉向但不會面向Vector（0,0,0）。我的對象必須面對Y軸。我不知道如何創建dir，up和rigth向量。我編輯我的Mainpost ..你可以看看嗎？或者是否有可能在Skype中添加你的東西或將來的幫助？ – ZeraTFK 2013-05-01 20:20:46

嗯，我明白了！

這就是我的解決方案：

public Matrix GetRotateToTargetMatrix(Vector3 TargetVector) 
{ 
      Matrix mBase = Matrix.Invert(Matrix.LookAtLH(new Vector3(0, 0, 0),  TargetVector, new Vector3(0, 1, 0))); 
      mBase.M44 = 1; 
      mBase.M14 = 0; 
      mBase.M24 = 0; 
      mBase.M34 = 0; 
      mBase.M41 = 0; 
      mBase.M42 = 0; 
      mBase.M43 = 0; 

      return = mBase; 
}

感謝Gnietschow和MHGameWork

來源

2013-05-04 14:18:53 ZeraTFK

C＃託管DirectX - 我如何旋轉網格到任何矢量？

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