檢查pygame中sprites中的多個碰撞

Question

我目前正在使用pygame，並且我想創建多個sprite並檢查至少兩個碰撞。我想出了兩個while循環的想法，但最終變得非常複雜。還有其他方法可以嘗試嗎？

Answer 1

使用pygame.sprite.spritecollide可以獲得與玩家碰撞的精靈列表，然後循環播放此列表以對碰撞的精靈進行操作。

還有groupcollide，您可以使用它來檢測兩個精靈組之間的衝突。它返回一個帶有組1的精靈的字典作爲鍵和組2的碰撞精靈作爲值。

import sys 
import pygame as pg 
from pygame.math import Vector2 


class Player(pg.sprite.Sprite): 

    def __init__(self, pos, *groups): 
     super().__init__(*groups) 
     self.image = pg.Surface((120, 60)) 
     self.image.fill(pg.Color('dodgerblue')) 
     self.rect = self.image.get_rect(center=pos) 


class Enemy(pg.sprite.Sprite): 

    def __init__(self, pos, *groups): 
     super().__init__(*groups) 
     self.image = pg.Surface((120, 60)) 
     self.image.fill(pg.Color('sienna1')) 
     self.rect = self.image.get_rect(center=pos) 


def main(): 
    screen = pg.display.set_mode((640, 480)) 
    clock = pg.time.Clock() 
    all_sprites = pg.sprite.Group() 
    enemy_group = pg.sprite.Group(Enemy((200, 250)), Enemy((350, 250))) 
    all_sprites.add(enemy_group) 
    player = Player((100, 300), all_sprites) 

    done = False 

    while not done: 
     for event in pg.event.get(): 
      if event.type == pg.QUIT: 
       done = True 
      elif event.type == pg.MOUSEMOTION: 
       player.rect.center = event.pos 

     all_sprites.update() 
     # Check which enemies collided with the player. 
     # spritecollide returns a list of the collided sprites. 
     collided_enemies = pg.sprite.spritecollide(player, enemy_group, False) 

     screen.fill((30, 30, 30)) 
     all_sprites.draw(screen) 
     for enemy in collided_enemies: 
      # Draw rects around the collided enemies. 
      pg.draw.rect(screen, (0, 190, 120), enemy.rect, 4) 

     pg.display.flip() 
     clock.tick(30) 


if __name__ == '__main__': 
    pg.init() 
    main() 
    pg.quit() 
    sys.exit()