熊貓合併兩個dataframes具有相同的結構

Question

假設我有兩個dataframes：

x1 x2 x3 
y1 a1 a1 a1  
y2 b1 b1 b1  
y3 c1 c1 c1 

    x1 x2 x3 
y1 a2 a2 a2  
y2 b2 b2 b2  
y3 c2 c2 c2   

這是從同一個地方在得到以下數據框中每個元素的兩個值的列表，最簡單的方法原始數據框？

x1  x2  x3 
y1 [a1,a2] [a1,a2] [a1,a2]  
y2 [b1,b2] [b1,b2] [b1,b2]  
y3 [c1,c2] [c1,c2] [c1,c2] 

Answer 1

使用applymap

In [953]: df1.applymap(lambda x: [x]) + df2.applymap(lambda x: [x]) 
Out[953]: 
      x1  x2  x3 
y1 [a1, a2] [a1, a2] [a1, a2] 
y2 [b1, b2] [b1, b2] [b1, b2] 
y3 [c1, c2] [c1, c2] [c1, c2] 

Answer 2

一（出許多）可能的解決方案：

In [63]: d1.astype(str).add(',').add(d2.astype(str)).apply(lambda x: x.str.split(',')) 
Out[63]: 
      x1  x2  x3 
y1 [a1, a2] [a1, a2] [a1, a2] 
y2 [b1, b2] [b1, b2] [b1, b2] 
y3 [c1, c2] [c1, c2] [c1, c2]