在Java中使用帶符號的二進制數進行二進制加法和減法

Question

爲了享受純粹的樂趣和我的時間，我想了解更多關於二進制數字和程序集的知識。我去過當地圖書館查閱一些書籍，以便更好地瞭解二進制數字和加法。幾個星期前我甚至都不知道，可以用Java添加二進制數字。我迷迷糊糊，已經兩天了。

就像我說的，我試圖在加法和減法中加入二進制數。我假設我需要解析所有內容才能正常工作。我覺得我在這裏找點東西。缺少什麼？任何幫助都有幫助。

至於現在，我有這樣的：

`import java.util.Scanner; 
public class binary operation { 
public static void main(String[]args){ 
    Scanner keyboard = new Scanner(System.in); 
    boolean keepGoing = true; 
    String binary1, binary2; 
    int num1, num2; 

    System.out.println("Scenario: Choose (A)dd, (S)ubtract, (E)xit"); 
    char choice = keyboard.next().charAt(0); 
    while(keepGoing){ 
     if (choice == 'A' || choice == 'a'){ 
      System.out.println("Enter 8-bit signed binary number: "); 
      binary1 = keyboard.next(); 
      System.out.println("Enter another binary number: "); 
      binary2 = keyboard.next(); 
      num1 = Integer.parseInt(binary1, 2); 
      num2 = Integer.parseInt(binary2, 2); 
      int sum = num1 + num2; 
      System.out.println(Integer.toBinaryString(sum)); 
     } 
     else if(choice == 'S' || choice == 's'){ 
      System.out.println("Enter 8-bit signed binary number: "); 
      binary1 = keyboard.next(); 
      System.out.println("Enter another binary number: "); 
      binary2 = keyboard.next(); 
      num1 = Integer.parseInt(binary1, 4); 
      num2 = Integer.parseInt(binary2, 4); 
      int difference = num1 - num2; 
      System.out.println(Integer.toBinaryString(difference)); 
     } 
     else if(choice == 'E' || choice == 'e'){ 
      System.out.println("Thank you."); 
      keepGoing = false; 
      System.exit(0); 
     } 
     if(keepGoing){ 
      System.out.println("Choose (A)dd, (S)ubtract, (E)xit"); 
      choice = keyboard.next().charAt(0); 
     } 
    } 

Answer 1

的toBinaryString始終打印爲32位無符號值。你需要一個像。

public static String toSignedBinary(int num) { 
    return num < 0 ? "-" + Long.toBinaryString(-(long) num) : Integer.toBinaryString(num); 
}