簡化Java布爾比較

Question

我發現一個方法等於比較兩個移動，我想簡化它。

public boolean equals(Object obj) { 
    if (obj == null) { 
     return false; 
    } 
    if (getClass() != obj.getClass()) { 
     return false; 
    } 
    final Move other = (Move) obj; 
    return !(this.initialBalls != other.initialBalls && 
      (this.initialBalls == null || !this.initialBalls.equals(other.initialBalls))) 
      && this.direction == other.direction && this.color == other.color; 
} 

有人有想法嗎？

Answer 1

您可以使用Apache Commons的EqualsBuilder。

public boolean equals(Object obj) { 
    if (obj == null) { return false; } 
    if (obj == this) { return true; } 
    if (obj.getClass() != getClass()) { 
     return false; 
    } 
    Move rhs = (Move) obj; 
    return new EqualsBuilder() 
     .appendSuper(super.equals(obj)) 
     .append(initialBalls, rhs.initialBalls) 
     .append(direction, rhs.direction) 
     .append(color, rhs.color) 
     .isEquals(); 
    }