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我想從2張圖像中找到相機extrinsics。我擁有CameraCalibration的內部函數，並且場景已知尺寸（使用3DSMAX創建）。相機extrinsics計算錯誤
棋盤是1000 * 1000，每個正方形125 * 125。相機處於（0,0,3000）處，直直看向以原點爲中心的棋盤。在第二圖像時，相機被轉換（-1500，0，-402）並旋轉30°在Y軸上再次指向棋盤的中心： 
GoodFeaturesToTrack正確地識別81角： 
我創建棋盤角的3d點，cvFindExtrinsicCameraParams2來計算intrinsics和cvRodrigues2來獲得旋轉矩陣。下面的代碼
Imports Emgu.CV
Imports Emgu.CV.Structure
Imports Emgu.CV.CvInvoke
Imports Emgu.CV.CvEnum
Imports Emgu.CV.UI
Imports System.Drawing
Imports System.IO
Imports System.Diagnostics
Imports System.Math
Module main_
Sub Main()
Const MAXFEATURES As Integer = 100
Dim featuresA(0)() As PointF
Dim featuresB(0)() As PointF
Dim features As Integer = 0
Dim imgA As Emgu.CV.Image(Of Emgu.CV.Structure.Bgr, Byte)
Dim imgB As Emgu.CV.Image(Of Emgu.CV.Structure.Bgr, Byte)
Dim grayA As Emgu.CV.Image(Of Emgu.CV.Structure.Gray, Byte)
Dim grayB As Emgu.CV.Image(Of Emgu.CV.Structure.Gray, Byte)
Dim pyrBufferA As Emgu.CV.Image(Of Emgu.CV.Structure.Gray, Byte)
Dim pyrBufferB As Emgu.CV.Image(Of Emgu.CV.Structure.Gray, Byte)
Dim pointsA As Matrix(Of Single)
Dim pointsB As Matrix(Of Single)
Dim flags As Emgu.CV.CvEnum.LKFLOW_TYPE = Emgu.CV.CvEnum.LKFLOW_TYPE.DEFAULT
Dim imagesize As Size
Dim termcrit As New Emgu.CV.Structure.MCvTermCriteria(20, 0.03D)
Dim status As Byte() = Nothing
Dim errors As Single() = Nothing
Dim red As Bgr = New Bgr(Color.Red)
' Load chessboards
imgA = New Image(Of [Structure].Bgr, Byte)("chessboard centre.jpg")
imgB = New Image(Of [Structure].Bgr, Byte)("chessboard left.jpg")
grayA = imgA.Convert(Of Gray, Byte)()
grayB = imgB.Convert(Of Gray, Byte)()
' setup for feature detection
imagesize = cvGetSize(grayA)
pyrBufferA = New Emgu.CV.Image(Of Emgu.CV.Structure.Gray, Byte)(imagesize.Width + 8, imagesize.Height/3)
pyrBufferB = New Emgu.CV.Image(Of Emgu.CV.Structure.Gray, Byte)(imagesize.Width + 8, imagesize.Height/3)
features = MAXFEATURES
' Find features
featuresA = grayA.GoodFeaturesToTrack(features, 0.01, 25, 3)
grayA.FindCornerSubPix(featuresA, New System.Drawing.Size(10, 10), New System.Drawing.Size(-1, -1), termcrit)
features = featuresA(0).Length
' Compute optical flow. Not necessary here but good to remember
Emgu.CV.OpticalFlow.PyrLK(grayA, grayB, pyrBufferA, pyrBufferB, featuresA(0), New Size(25, 25), 3, termcrit, flags, featuresB(0), status, errors)
Debug.Assert(featuresA(0).GetUpperBound(0) = featuresB(0).GetUpperBound(0))
' Copy features to an easier-to-use matrix and get min/max to create 3d points
Dim minx As Double = Double.MaxValue
Dim miny As Double = Double.MaxValue
Dim maxx As Double = Double.MinValue
Dim maxy As Double = Double.MinValue
pointsA = New Matrix(Of Single)(features, 2)
pointsB = New Matrix(Of Single)(features, 2)
For i As Integer = 0 To features - 1
pointsA(i, 0) = featuresA(0)(i).X
pointsA(i, 1) = featuresA(0)(i).Y
pointsB(i, 0) = featuresB(0)(i).X
pointsB(i, 1) = featuresB(0)(i).Y
If pointsA(i, 0) < minx Then
minx = pointsA(i, 0)
End If
If pointsA(i, 1) < miny Then
miny = pointsA(i, 1)
End If
If pointsA(i, 0) > maxx Then
maxx = pointsA(i, 0)
End If
If pointsA(i, 1) > maxy Then
maxy = pointsA(i, 1)
End If
Next
' Create 3D object points that correspond to chessboard corners
' (The chessboard is 1000*1000, squares are 125*125)
Dim corners As Integer = Sqrt(features)
Dim obj As New Matrix(Of Double)(features, 3)
Dim squaresize2dx As Double = (maxx - minx)/8 ' pixel width of a chessboard square
Dim squaresize2dy As Double = (maxy - miny)/8 ' pixel height of a chessboard square
For i As Integer = 0 To features - 1
obj(i, 0) = Math.Round((pointsA(i, 0) - minx)/squaresize2dx) * 125 ' X=0, 125, 250, 375 ... 1000
obj(i, 1) = Math.Round((pointsA(i, 1) - miny)/squaresize2dy) * 125 ' idem in Y
obj(i, 2) = 0
' Debug.WriteLine(pointsA(i, 0) & " " & pointsA(i, 1) & " " & obj(i, 0) & " " & obj(i, 1) & " " & obj(i, 2)) ' Just to verify
Next
' These were calculated with CalibrateCamera using the same images
Dim intrinsics As New Matrix(Of Double)({{889.1647, 0.0, 318.3721},
{0.0, 888.5134, 238.4254},
{0.0, 0.0, 1.0}})
' Find extrinsics
Dim distortion As New Matrix(Of Double)({-0.036302, 2.008797, -29.674306, -29.674306})
Dim translation As New Matrix(Of Double)(3, 1)
Dim rotation As New Matrix(Of Double)(3, 1)
cvFindExtrinsicCameraParams2(obj, pointsA, intrinsics, distortion, rotation, translation, False)
' Convert rotation vector to rotation matrix
Dim rotmat As New Matrix(Of Double)(3, 3)
Dim jacobian As New Matrix(Of Double)(9, 3)
cvRodrigues2(rotation, rotmat, jacobian)
' From http://en.wikipedia.org/wiki/Rotation_representation paragraph "Conversion formulae between representations"
Dim yr As Double = Asin(-rotmat(2, 0))
Dim xr As Double = Asin(rotmat(2, 1)/Cos(yr))
Dim zr As Double = Asin(rotmat(1, 0)/Cos(yr))
End Sub
End Module
的結果似乎不正確的，我期待的平移/旋轉，但我得到這個：
translation
208.394425348956
-169.447506344527
-654.273807995629
rotation
-0.0224937226554797
-2.13660350939653
-1.10542281290682
rotmat
-0.741100224945266 0.322885083546921 -0.588655824237707
-0.293966101915684 0.632206237134128 0.716867633983572
0.603617749499279 0.704315622822328 -0.373610915174894
xr=1.08307908108382 yr=-0.648031006135158 zr=-0.377625254910525
xr=62.0558602250101° yr=-37.1294416451609° zr=-21.636333343925°
會有人有一個想法，我做錯了嗎？謝謝！
+1向我介紹cvRodrigues2（）。乾杯! – coder9