下面是一些基於https://github.com/kevinhughes27/pyIPCA增量PCA碼這是CCIPCA方法的實現。
import scipy.sparse as sp
import numpy as np
from scipy import linalg as la
import scipy.sparse as sps
from sklearn import datasets
class CCIPCA:
def __init__(self, n_components, n_features, amnesic=2.0, copy=True):
self.n_components = n_components
self.n_features = n_features
self.copy = copy
self.amnesic = amnesic
self.iteration = 0
self.mean_ = None
self.components_ = None
self.mean_ = np.zeros([self.n_features], np.float)
self.components_ = np.ones((self.n_components,self.n_features))/\
(self.n_features*self.n_components)
def partial_fit(self, u):
n = float(self.iteration)
V = self.components_
# amnesic learning params
if n <= int(self.amnesic):
w1 = float(n+2-1)/float(n+2)
w2 = float(1)/float(n+2)
else:
w1 = float(n+2-self.amnesic)/float(n+2)
w2 = float(1+self.amnesic)/float(n+2)
# update mean
self.mean_ = w1*self.mean_ + w2*u
# mean center u
u = u - self.mean_
# update components
for j in range(0,self.n_components):
if j > n: pass
elif j == n: V[j,:] = u
else:
# update the components
V[j,:] = w1*V[j,:] + w2*np.dot(u,V[j,:])*u/la.norm(V[j,:])
normedV = V[j,:]/la.norm(V[j,:])
normedV = normedV.reshape((self.n_features, 1))
u = u - np.dot(np.dot(u,normedV),normedV.T)
self.iteration += 1
self.components_ = V/la.norm(V)
return
def post_process(self):
self.explained_variance_ratio_ = np.sqrt(np.sum(self.components_**2,axis=1))
idx = np.argsort(-self.explained_variance_ratio_)
self.explained_variance_ratio_ = self.explained_variance_ratio_[idx]
self.components_ = self.components_[idx,:]
self.explained_variance_ratio_ = (self.explained_variance_ratio_/\
self.explained_variance_ratio_.sum())
for r in range(0,self.components_.shape[0]):
d = np.sqrt(np.dot(self.components_[r,:],self.components_[r,:]))
self.components_[r,:] /= d
您可以
進口大熊貓作爲PD,ccipca
df = pd.read_csv('iris.csv')
df = np.array(df)[:,:4].astype(float)
pca = ccipca.CCIPCA(n_components=2,n_features=4)
S = 10
print df[0, :]
for i in range(150): pca.partial_fit(df[i, :])
pca.post_process()
得到的特徵向量/值不會exaactly是相同批次PCA測試。結果是近似的,但它們很有用。
好的,所以ti基本上和我手動做同樣的事情。謝謝你的幫助。 – Marko