2011-10-27 40 views
0

我想實現拉普拉斯值,這是我的內核:西格瑪和偏差0

0 1 0 
1 -4 1 
0 1 0 

我只顯示相關的代碼,我有一個3x3的陣列Pixel存儲的相鄰像素值

Pixel[i][j].val[k]分別表示k=0,1,2的值爲RBG

long double kernel[3][3],mean=0,nTemp=0,c,sum=0,n=0,s=0,d=0; 

for (row = 1; row < rows - 2; row++) 
    { 
     for (col = 1; col < cols - 2; col++) 
     { 
      nTemp = 0.0; 
      for (i=0 ; i < 3; i++) 
      { 
       for (j=0 ; j < 3; j++) 
       { 
         c = (Pixel[i][j].val[0]+Pixel[i][j].val[1]+Pixel[i][j].val[2])/3; 
         nTemp += (double)c * kernel[i][j]; 
       } 
      } 

      sum += nTemp; 
      n++; 
     } 
    } 


for (row = 1; row < rows - 2; row++) 
    { 
     for (col = 1; col < cols - 2; col++) 
     { 
      nTemp = 0.0; 

      for (i=0 ; i < 3; i++) 
      { 
       for (j=0 ; j < 3; j++) 
       { 
         c = (Pixel[i][j].val[0]+Pixel[i][j].val[1]+Pixel[i][j].val[2])/3; 

         nTemp += (double)c * kernel[i][j]; 
       } 
      } 

      s = (mean - nTemp); 
      d += (s * s); 
     } 
    } 
// PROBLEM IS HERE SIGMA (s) and Deviation (d) are always 0, 

我得到一個完全變黑的圖像,請告訴我我哪裏出錯了?

回答

1

您只有在內部循環中使用像素[i] [j]爲0 <= i, j < 3,應該不是Pixel[row+i][col+j]

+0

Y ....剛剛意識到..arrghh ...給我幾分鐘...謝謝 –

+0

Y固定...非常感謝丹尼爾再次輸入.. –