2014-04-25 99 views
3

所以我有一個轉變的發車位置到全球空間的方法:四元數反轉?

public Vector3 GridToGlobal(IVector3 gridPos) 
{ 
Vector3 globalPos = new Vector3(gridPos.x, gridPos.y, gridPos.z); 
globalPos *= Scale; 
globalPos = Container.transform.rotation * globalPos; 
return globalPos; 
} 

現在,當我想要做的相反,我將如何去矢量旋轉到電網空間?

public IVector3 GlobalToGrid(Vector3 globalPos) 
    { 
     globalPos -= Container.transform.position; 
     globalPos = Container.transform.rotation * globalPos; //this will obviously rotate in the wrong direction 
     globalPos /= Scale; 
     return new IVector3((int)Mathf.Round(globalPos.x), (int)Mathf.Round(globalPos.y), (int)Mathf.Round(globalPos.z)); 
    } 

任何想法?

回答