我已經使用這個方程,以獲得執行時間方程: Execution time = Cpu time + memory time
然後, Execution time = (#instructions * average instruction execution time) +
(Misses Cache l1 * latency L2) +
(Misses Cach
介紹 在this question我們可以學習如何禁用L1緩存爲一個單個可變。 這裏是公認的答案: As mentioned above you can use inline PTX, here is an example: __device__ __inline__ double ld_gbl_cg(const double *addr) {
double return_value;